524	NICHOLLS'S SEAMANSHIP AND NAUTICAL KNOWLEDGE
From hold	Tons	Distance	Moment in
from T.C.	foot-tons
No.   1	500	150 F.	75000 Ford.
2	67	88 F.	5896     „
 3	125    ,	23 F.	2875     „
 4	370	100 A.	37000 Aft
 5	150	152 A.	22800 Aft.
1212	83771 Ford.
		59800 Aft.
The resultant decrease of moment	23971 Ford.

feet
tons   130
forward
e
_ ,     .
I   I      ^1    I    l
Fig   43.

tons       1212     nft rt .    ,
Mean rise —	= - =22*9 inches
T.P.I.       53
Total trim = 23971 -f- 14:23=16-8 indies
Forward	Aft
ft.    ins	ft. ins.
Original draught	22   01	24    10
Mean decrease	110-9	1    10-9
20   02-1      *     22    11-1
Half total trim	-         8-4        +         84
New draught	19     5*7	23     7-5
Example.—Assuming the ship's draught as in .previous question
to be 19 ft. 5 -7 ins. forward, 23 ft. 7*5 ins. aft, required to find the distance
400 tons will need to be moved to bring the ship on to an even keel;
LT.M. 1423.
ft.   ins.
Draught forward         19   05-7
aft	23   07-5
Total trim	4   01-8 = 49-8 inches