PARALLELOGKAM OP JTOECBS 267 When a ship steams at the rate of 10 knots directly into the teeth of a 40 miles per hour gale (force 8 on the Beaufort Scale), the velocity of the wind as registered by an anemometer on deck would be 50 m.p.h., and, conversely, if she were going in the opposite direction at 10 knots she would be running before the wind and the anemometer would register 30 m.p.h., that is 40 m.p h less 10 knots The anemometer registers the apparent wind, which is the resultant effect of the true wind and the current of air due to the ship's motion. Suppose a ship to be stopped, heading North, and the wind to be blowing from East at the rate of 20 m p h., then the wind would be on the starboard beam and the steamer's- smoke would trail to the port beam at 20 rn p.h. If the ship now gets under way and steams j^orth at 10 knots, the wind would appear to come from the starboard bow and the smoke would trend towards the port quarter. But how far abaft the beam? The par- allelogram of forces will help us 'as illustrated m Figure 8. Fig 8 —True Wind East; Apparent Wind N 63° E From the ship A draw AB, West, and mark ofE 20 parts from* any convenient scale of equal parts, then draw AC, South, and make it equal to 10 of the same parts. Complete the parallelogram by drawing CD parallel to AB and DB parallel to AC. The diagonal AD is the resultant of the two velocities (wind and ship) and^gives the direction the steamer's smoke would go. AD is the direction of the apparent wind as felt on board the ship, and its length, measured from the scale of equal parts, will be its velocity. The apparent wind comes from N. 63° E., velocity 22£ m.p.h., and the smoke will, of course, go S. 63° W. Another Example.—Given a true wind from N.E , at 10 m.p.h., ship steaming East, 12 m.p.h. Find the direction and velocity of the apparent wind. Draw AB to the S.W. and equal to 10 units. Draw AC to the East and equal to 12 units. Join CB. Then CB is the apparent wind. Ans.—N. 69° E., 20 m.p.h. APPARENT Fig. 9.—True Wind NE.; Apparent Wind N. 69° E. It will be noted that half the parallelogram is really all that is needed and ABC is called the triangle, of forces