270 NICHOLLS'S SEAMANSHIP AND NAUTICAL KNOWLEDGE apparatus will illustrate very clearly the corresponding changes in the angles formed by the pendants and the tensions on the spans. It will be recognised that the greater tension will be on the span which is nearer to the vertical and that the tension on each will be at its maximum when the span is taut, as seamen say when the pendants form nearly a straight line between the pulleys. The same results may be arrived at by construction as follows:— Example —Two pendants form a span slung between two masts making angles with the vertical of 22 and 53 degrees. Find the tension on each arm, or pendant, of the span when supporting a weight of 2J tons. Construction — Draw two parallel vertical lines to represent the masts; make angles K and Y equal to 22 and 53 degrees respectively. Points X and Y are placed anywhere on the masts and w>&r/fnn.nin/HMiiiffnrmh*. Fig. 13 represent the positions where the ends of the pendants are made fast The lines of the angles intersect at A. Now draw AB vertically up- wards and equal in length to 2£-ton units from a scale of equal parts. Draw EC parallel to one span and BD parallel to the other. The length of AD represents the tension (1 ton) on the arm from 7, and AC the tension (2 tons) on the arm from X. Another Method is to give the lengths of the pendants and the heights of their standing ends above the deck as measured from the rigging plan of the ship, then draw out the facts to scale and construct the parallelogram. Example. — The horizontal distance between two vertical masts is 80 feet. The end of one pendant, 60 feet long, is 80 ft Flg. 14. made fast 100 feet up one mast and the end of another pendant, 50 feet long, is made fast 70 feet up the other mast. It is intended to lift a 10-ton boiler by using the pendants as span. Find the tension on eack