524 NICHOLLS'S SEAMANSHIP AND NAUTICAL KNOWLEDGE

From hold Tons Distance Moment in

from T.C. foot-tons

No. 1 500 150 F. 75000 Ford.

2 67 88 F. 5896 „

3 125 , 23 F. 2875 „

4 370 100 A. 37000 Aft

5 150 152 A. 22800 Aft.

1212 83771 Ford.
------ 59800 Aft.

The resultant decrease of moment 23971 Ford.

FEET
TONS 130

FORWARD
e

_ , .

I I ^1 I l

Fig 43.

tons 1212 nft rt . ,
Mean rise — = - =22*9 inches

T.P.I. 53

Total trim = 23971 -f- 14:23=16-8 indies

Forward Aft

ft. ins ft. ins.

Original draught 22 01 24 10

Mean decrease 110-9 1 10-9

20 02-1 * 22 11-1
Half total trim - 8-4 + 84

New draught 19 5*7 23 7-5

Example.—Assuming the ship's draught as in .previous question
to be 19 ft. 5 -7 ins. forward, 23 ft. 7*5 ins. aft, required to find the distance
400 tons will need to be moved to bring the ship on to an even keel;
LT.M. 1423.

ft. ins.

Draught forward 19 05-7
aft 23 07-5

Total trim 4 01-8 = 49-8 inches