INDUCTOR MACHINES

277

alternator, if <£>0 is the amplitude of flux pulsation through the
armature coil, as derived from the required induced voltage by
equation (1), let:

p = number of inductor teeth, that is,
number of pairs of poles (four in
the eight-polar machine, Fig. 136).
pi = magnetic reluctance of air gap in front
of the inductor tooth, which should
be as low as possible,

p2 = magnetic reluctance of leakage path
through inductor slot into the arma-
• ture coil, which should be as high as
possible,

and as:

it follows:

= 2

Pl

P2

P2

P2 — PI
Pi .

I ;

P2 ~ Pi

(3)

(4)

(5)

and the total flux through the magnetic circuit, C, and out from
all the p inductor teeth and slots thus is:

= P
__ cy

P2J+_P1
P2 — Pi

P2 —

(6)

In the corresponding standard alternator, with 2 p poles, the
total flux entering the armature is:

and if pi is the reluctance of the air gap between field pole and
armature face, p2 the leakage reluctance between the field poles,
the ratio of the leakage flux between the field poles, <£>', to the

armature flux, $o> is:

i i

(7)
(8)

hence :

Pl

Pi?
w