INDUCTION MOTOR

73

and the equations are:
in primary circuit:

in secondary circuit:

sE\ = sEz
and, current:

From (6) follows:

and, substituting (7) into (5):
hence:

+

substituting (8) into (4) gives:

sZ0

and, transposed:

Jo

r? + ^o

Denoting:

= r

and:

&

s

it is, substituting into (9) and (10) :

#o (1 + Z'Y) = $2+ (Z1 + Z0

Z'ZBY)

.(4)

(5)
(6)

(7)

(8)

(9)
(10)

(11)

(12)
(13)