SINGLE-PHASE INDUCTION MOTOR

115

or, for:

b = 1; a = 0.5;

Fi + 2 7 + 72

2 7x + 4 7 + 72

7] + 27
2 7i + 4 7 + 72'

(74)

and the primary current, or single-phase supply current is, by
substituting (73) into (65):

(75)

or, for:

6 = l;a = 0.5:

1 + 27)(71 + 27+72)
2 Yl + 4 7 + 72 "'

(76)

and herefrom follows, by reducing to absolute values, the torque,
torque ratio, volt-ampere input, apparent torque efficiency, etc.
Or, denoting:

it is:
(70):

P

Y + - Y + 72 = 7',
a

= ~~ = m (cos <t> + j sin

(77)

(78)

(73):

F°

(79)

(75):

(80)

!T = Aerfz sin <£,
Q = 6($o;
and for a quarter-phase motor, with voltage —7^ impressed per