REGULATING POLE CONVERTERS

441

Due to the third harmonic, t, and the angle of shift of the field
flux, Ta, the voltage ratio differs from the normal by the factor:

(1 + t) cosVa,
and the ring voltage of the converter thus is:

E =
hence, by (1):

(1 + t) COS ra'

(3)

EQ sin

T7f ___

JLJ —

n

(4)

A/2 (1 + t) COSTa

and the power component of the ring current corresponding to
the direct-current output thus is, when neglecting losses, from

(2):

If = 1° (1 + t) COS Ta

COS Ta

(5)

n sm

n

Due to the loss, pi, in the converter, this current is increased by
(1 + PI) in a direct converter, or decreased by the factor
(1 — pi) in an inverted converter.

The power component of the alternating current thus is:

= r (i + pi)

T
= jf

COSTq

. TT

n sin --
n

(6)

where pi may be considered as negative in an inverted converter.
With the angle of lag 0i, the reactive component of the current
is:

/2 = /]_ tan 0i,

and the total alternating ring current is:

r_

T =

COS I

_ JoV2(l+Q (1+Pl) COSTg

n sin - cos
n

(7)

Ih

if

fir,1 *

I