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and if p be the density, the whole kinetic energy of the motion is
Again, if P be the pressure at infinity and R0 the initial value of R, the work done is
.                                                                      j; ii J.      , -if)           TJ<)\
5 (_K0'  IV).
When we equate (2) and (3) we get
    2P fRns     ,
expressing the velocity of the boundary in terms of the radius.    Also, since U=dR/dt, 
if /3 = R/R0. The time of collapse to a given fraction of the original radius is thus proportional to R0p^P~^, a result which might have been anticipated by a consideration of "dimensions." The time T of complete collapse is obtained by making /3 == 0 in (5). An equivalent expression is given by Besant, who refers to Cambridge Senate House Problems of 1847.
Writing ft3 = z, we have
/* 1      /QU/2 W M                  r 1          -
I         p~t     \A}[>J         ii         _T/T         \ . *    7
Jo(l-/33)^~   hZ which may be expressed by means of F functions.    Thus
According to (4) U increases without limit as R diminishes. This indefinite increase may be obviated if we introduce, instead of an internal pressure zero or constant, one which increases with sufficient rapidity. We may suppose such a pressure due to a permanent gas obedient to Boyle's law. Then, if the initial pressure be Q, the work of compression is 4>7rQRo8 log (R0/R), which is to be subtracted from (3). Hence
a,nd U= 0 when
2 denoting (as before) the ratio of volumes RS/R0S. Whatever be the (positive) yalue of Q, U comes again to zero before complete collapse, and if Q >P the first movement of the boundary is outwards. The boundary oscillates between bwo positions, of which one is the initial..............................(1)