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```HEAT CAPACITY AND  CALORIFIC  INTENSITY CURVES    359

80 per cent air supply.    Assumed that CH4 dissociates, that 90 per cent
will be burned.    02 available = 32.85X0.8 =26.28.

80% Air Supply
Calories
Products of Combustion

02
H2
CO
C02
H2O
N2

H2   16.60X0.9 = 14.94X58.2 = CH3 5.50     Dissociates H2   11.0 X0.9= 9.90X58.2 = C       5.50                        X97.6 = 26.28-17.92=8.36
CO 27.10             16.72X68.2 = C02  3.90 N2   46.30 H20 0.60
F
870
576 537
1141
7.47
4.95 5.50
1.66 1.10

14.94 9.90
29.88
19.80 22.00
33.44 46.30

5.50

10.38
16.72 3.90

17.92 8.36

0.60

3124
26.28
2.76
10.38
26.12
25.34
151.42

60 per cent air supply.    Assumed that CH3 dissociates, 80 per cent of H2
will be burned.    O2 available = 32.85X0.6 = 19.71.

60% Air Supply
Calories
Products of Combustion

02
H2
CO
CO2
H2O
N2

H2   16.60X0.8 = 13.28X58.2 = CH4 5 . 50   Dissociates H2   11.00X0.8= 8.80X58.2 = C       5.50                        X97.6 = CO 27.10 19.71-16.54 = 3.17 6.34X68.20 =
A
773
512 537
6.64
4.40 5.50
3.32 2.20

13.28 8.80
26.56
17.60 22.00
12.68 46.30

5 50

20.76
6.34 3.90
0.60

16.54 3.17

432

2254
19.71
5.52
20.76
15.74
22.68
125.14

100 per cent air supply, products of combustion: N2 = 177.70
80 per cent air, products of combustion:

N2-fCO-f-H2 = 151. 42+10. 38+2.76 = 164. 56.
60 per cent air, products of combustion :

2 = 125.14+20.76-h5.52 = 151.42.

The assumption is made that air = l volume O2 and 4 volumes of N2;
that 5 volumes of air are required to supply 1 volume O2. This allows for
moisture in fuel and air supply.```