TH 5G19 .A5 I j^'ji^i^si JIK ^LSA .E "11 1 1 Es: NOIS Book ,KS Gopglit)^* COPVRICHT DEPOSm THE STEEL SQUARE INSTRUCTION PAPER PREPARKD BY Morris Wili^tams Writrr and Expert on Carpentry and Building AMEiRICAN SCHOOL OF COR RESPONDEJNCE v\ CHICAGO IIvLINOIS U.S.A. LIBRARY of CONtiKESS I wo Copies rieceivtx: JUN 13 iyo8 OQHY B. / Copyright 1908 by American Schooi. of Correspondence Entered at Stationers' Hall, I^ondon All Rights Reserved I THE STEEL SQUARE INTRODUCTORY The Standard Steel Square has a blade 24 Inches long and 2 inches wide, and a tongue from 14 to 18 inches long and 1 J inches wide. The blade is at right angles to the tongue. The face of the square is shown in Fig. 1. It is always stamped with the manufacturer's name and number. The reverse is the hack (see Fig. 2). The longer arm is the blade; the shorter arm, the tongue. In the center of the tongue, on the face side, will be found two parallel lines divided into spaces (see Fig. 1); this is the octagon scale. The spaces will be found numbered 10, 20, 30, 40, 50, 60, and 70, when the tongue is 18 inches long. To draw an octagon of 8 inches square, draw a square 8 inches each way, and draw a perpendicular and a horizontal line through its center. To find the length of the octagon side, place one point of a com- pass on any of the main divisions of the scale, and the other point of the compass on the eighth subdivision ; then step this length off on each side of the center lines on the side of the square, which will give the points from which to draw the octagon lines. The diameter of the octagon must equal in inches the number of spaces taken from the square. On the opposite side of the tongue, in the center, will be found the brace rule (see Fig. 3). The fractions denote the rise and ru7i of the brace, and the decimals the length. For example, a brace of 36 inches run and 36 inches rise, will have a length of 50.91 inches; a brace of 42 inches run and 42 inches rise, will have a length of 59.40 inches; etc. On the back of the blade (Fig. 4) will be found the board measure, where eight parallel lines running along the length of the blade are shown and divided at every inch by cross-lines. Under 12, on the outer edge of the blade, will be found the various lengths of the boards, as 8, 9, 10, 11, 12, etc. For example, take a board 14 feet long and 9 THE STEEL SQUARE (\j =L. O 0) CO — (0 r^ in — B- ^ r^ (0 6) - 00 1^ - 10 10 _ t - n - c\J iiililililililiiilili'ililili Z= CVJ — CO <^i^ (0jM | OjO- ^ O — 0) 9o)jONo)|;roo lOlOQcOcO^'OJ 0)[O|O,-iCvj^^(0 otq =r ^ — fO ^ ^ 1 1 1 1 1 1 1 OlOO(o gAl c\l<DiO N N COO) 00 LO CO THE STEEL SQUARE THE STEEL SQUARE Fig. 5. Use of Steel Square to Find Miter and Side of Pentagon. inches wide. To find the contents, look under 12, and find 14; then fol- low this space along to the cross-line un- der 9, the width of the board ; and here is found 10 feet 6 inches, denoting the contents of a board 14 feet long and 9 inches wide. To Find the Mi= ter and Length of Side for any Poly= gon, with the Steel Square. In Fig. 5 is shown a pentagon figure. The miters of the pentagon stand at 72* degrees with each other, and are found by dividing 360 by 5, the number of sides in the pentagon. But the angle when applied to the square to obtain the miter, is only one-half of 72, or 36 degrees, and intersects the blade at 8f |, as shown in Fig. 5. By squaring up from 6 on the tongue, intersecting the degree line at a, the center a is determined either for the inscribed or the circumscribed di- ameter, the radii being a h and a c, respec- tivelyo The length of the sides will be 8f | inches to the foot. If the length of the inscribed diameter be 8 feet, then the sides would b- ^ ^ 8|| inches. Mill Fig. 6. Use of Steel Square to Find Miter and Side of Hexagon. THE STEEL SQUARE The figures to use for other polygons are as follows: Triangle 20|f Square 12 Hexagon 7 Nonagon 4f Decagon 3f In Fig. 6 the same process is used in finding the miter and side of the hexagon polygon. To find the degree line, 360 is divided by 6, the num- ber of sides, as follows: 360 -^ 6 = 60; and 60 -^ 2 = 30 degrees. Now, from 12 on tongue, draw a line making an angle of 30 degrees with the tongue. It wdll cut the blade in 7 as shown; and from 7 to m, the heel of the square, will be the length of the side. From 6 on tongue, erect a line to cut the degree line in c; and with c as center, describe a circle having the radius of c 7; and around the circle, complete the hexagon by taking the length 7 m with the compass for each side, as shown. In Fig. 7 the same process is shown applied to the octagon. The degree line in all the polygons is found by dividing 360 by the number of sides in the figure: 360 -^ 8 = 45; and 45 -^ 2 = 22 J degrees. This gives the degree line for the octagon. Complete the process as was described for the other polygons. By using the following figures for the various polygons, the miter lines may be found ; but in these figures no account is taken of the relative size of sides to the foot as in the figures preceding: Triangle 7 in. and 4 in. Pentagon 11 " " 8 " Hexagon 4 " " 7" Heptagon n\ " " 6" Fig. 7. Use of Steel Square to Find Miter and Side of Octagon. THE STEEL SQUARE Fig. 8. Use of Square to Find Miter of Equilateral Triangle. Octagon 17 in. and 7 in. Nonagon 22^ '' "9" Decagon 9i " " 3 " The miter is to be drawn along the Hne of the first cohimn, as shown for the triangle in Fig. 8, and for the hexagon in Fig. 9. In Fig. 10 is shown a diagram for finding degrees on the square. For example, if a pitch of 35 degrees is re- quired, use 8J|- on tongue and 12 on blade ; if 45 degrees, use 12 on tongue and 12 on blade; etc. In Fig. 11 is shown the relative length of run for a rafter and a hip, the rafter being 12 inches and the hip 17 inches. The reason, as shown in this diagram, why 17 is taken for the run of the hip, in- stead of 12 as for the common rafter, is that the seats of the com- mon rafter and hip do not run parallel with each other, but di- verge in roofs of equal pitch at an angle of 45 degrees; therefore, 17 inches taken on the run of the hip is equal to only 12 inches when taken on that of the common rafter, as shown by the dotted line from heel to heel of the two squares in Fig. 11. In Fig. 12 is shown how other figures on the square may be found for corners that deviate from the 45 degrees. Fig. 9. Use of Square to Find Miter of Hexagon. It is shown that THE STEEL SQUARE Fig. 10. for a pentagon, which makes a 36-degree angle with the plate, the figure to be used on the square for run is 14| inches; for a hexagon, \r which makes a 30-degree angle with the plate, the figure will be I3f inches; and for an octagon, which makes an angle of 22J de- grees with the plate, the figure to use on the square for run of hip to corre- spond to the run of the common rafters, will be 13 inches. It will be observed that the height in each case is 9 inches. Fig. 13 illustrates a method of finding the relative height of a hip or valley per foot run to that of the common raf- ter. The square is shown placed with 12 on blade and 9 on tongue for the common rafter; and shows that for the hip the rise is only 6j\ inches. The Steel Square as Applied in Roof Fram= Pig. 11. Square Applied to Determine Relative inff. Roof framing at Length of Run for Rafter and Hip. ** ^ ° ^ present is as simple as it possibly can be, so that any attempt at a new method would be super- Diagram for Finding Pitches of Various Degrees by Means of the Steel Square. THE STEEL SQUARE fluous. There may, however, be a certain way of presenting the sub- ject that will carry with it almost the weight assigned to a new theory, making what is already simple still more simple. The steel square is a mighty factor in roof framing, and without doubt the greatest tool in practical potency that ever was invented / //^ R\ir\ of ComTTnori Rafter ^ 9 {,n,, ,,,,,, 11 iin 12 la /J "';^ """1 ^y// '^% ■^ ■^y ^\S ^ / ^^sH -y ^ ^ Pig. 12. Use of Square to Determine Length of Run for Rafters on Corners Other than 4.5°. for the carpenter. With its use the lengths and bevels of every piece of timber that goes into the construction of the most intricate design of roof, can easily be obtained, and that with but very little knowledge of lines. In roofs of equal pitch, as illustrated in Fig. 14, the steel square is all that is required if one properly understands how to handle it. THE STEEL SQUARE What is meant by a pitch of a roof, is the number of inches it rises to the foot of run. In Fig. 15 is shown the steel square with figures representing Fig. 13. Method of Finding Relative Height of Hip or Valley per Foot of Run to that of Common Rafter. the various pitches to the foot of run. For the J-pitch roof, the figures as shown, from 12 on tongue to 12 on blade, are those to be used on the steel square for the common rafter; and for f pitch, the figures to be used on the square will be 12 and 9, as shown. Fig. 14, Diagram to Illustrate Use of Steel Square in Laying Out Timbers of Roofs of Equal Pitch. To understand this figure, it is necessary only to keep in mind that the pitch of a roof is reckoned from the span. Since the run in each pitch as shown is 12 inches, the span is two times 12 inches, which 10 THE STEEL SQUARE equals 24 inches; hence, 12 on blade to represent the foot run, and 12 on tongue to represent the rise over J the span, will be the figures on the square for a ^-pitch roof. For the | pitch, the figures are shown to be 12 on tongue and 9 on blade, 9 being J of the span, 24 inches. The same rule applies to all the pitches. The 4 pitch is shown to rise 4 inches to the foot of run, because 4 inches is J of the span, 24 inches, the ^ pitch is shown to rise 8 inches to the foot of run, because 8 inches is J of the span, 24 inches; etc. The roof referred to in Figs. 16 and 17 is to rise 9 inches to the foot of run; it is therefore a |-pitch roof. For all the common rafters, the fig- ures to be used on the square will be 12 on blade to represent the run, and 9 on tongue to represent the rise to the foot of run; and for all the hips and valleys, 17 on blade to represent the run, and 9 on tongue to represent the rise of the roof to the foot of run. Why 17 represents the run for all the hips and valleys, will be understood by examining Fig. 19, in which 17 is shown to be the diag- onal of a foot square. In equal-pitch roofs the corners are square, and the plan of the hip or valley will always be a diagonal of a square corner as shown at 1, 2, 3, and 5 in Fig. 14. In Fig. 18 are shown ^ pitch, I pitch and J pitch over a square corner. / I I I tsj^ "ST C\J Tv OJ cu ^ -^ -35 W "iJ5 ■^ "5 lo -c\j 2 Pitch / ii /-= 24 / tl 3 "07 -6 y i / CO 7 "n 54 .^ -io 24 ^"W 6 In i "cm 12 -3 h 10 |9 16 |7 16 \5 K 13 \2 H Fig. 15. Steel Square Giving Various Pitches to Foot of Run. The figures to be used on the square for the hip, will be 17 for run in each case. For the ^ pitch, the figures to be used would be 17 inches run and 4 inches rise, to correspond with the 12 inches run and 4 inches rise of the common rafter. For the f pitch, the figures to be used for hip would be 17 inches run and 9 inches rise, to corre- I i THE STEEL SQUARE 11 spond with the 12 inches run and 9 inches rise of the common rafter; and for the ^1 pitch, the figures to be used on the square will be 17 inches run and 12 inches rise, to correspond with the 12 inches run and 12 inches rise of the common rafter. It will be observed from above, that in all cases where the plan of the hip or valley is a diagonal of a square, the figures to be used on Top cut for i3ft.6in. Plurr>b Cut Top cut for i3ft/ \ \ \ Fig. 16. Method of Laying Out Common Rafters of a %-Pitcli Roof. the square for run will be 17 inches; and for the rise, whatever the roof rises to the foot of run. It should also be remembered that this is the condition in all roofs of equal pitch, where the angle of the hip or valley is a 45-degree angle, or, in other words, where w^e have the diagonal of a square. It has been shown in Fig. 12 how other figures for other plan angles may be found; and that in each case the figures for run vary Heel cut of hip T op cut for laft.ein. run of hip Top cut for 13 ft. run' of hip Fig. 17. Method of Laying Out Hips and Valleys of a -/s-Pitch Roof. according to the plan angle of the hip or valley, while the figure for the height in each case is similar. In Fig. 14 are show^n a variety of runs for common rafters, but all have the same pitch; they rise 9 inches to the foot of run. The main 12 THE STEEL SQUARE roof is shown to have a span of 27 feet, which makes the run of the common rafter 13 feet 6 inches. The run of the front wing is shown to be 10 feet 4 inches; and the run of the small gable at the left corner of the front, is shown to be 8 feet. The diversity exhibited in the runs, and especially the fractional part of a foot shown in two of them, will afford an opportunity to treat of the main difficulties in laying out roof timbers in roofs of equal pitch. Let it be determined to have a rise of 9 inches to the foot of run; and in this connec- tion it may be well to re- member that the propor- tional rise to the foot run for roofs of equal pitch makes not the least dif- ference in the method of treatment. To lay out the common rafters for the main roof, which has a run of 13 feet 6 inches, proceed as shown in Fig. 16. Take 12 on the blade and 9 on the tongue, and step 13 times along the rafter timber. This will give the length of rafter for 13 feet of run. In this example, however, there is another 6 inches of run to cover. For this additional length, take 6 inches on the blade (it being J a foot run) for run, and take J of 9 on the tongue (which is 4 J inches), and step one time. This, in addition to what has already been found by stepping 13 times with 12 and 9, will give the full length of the rafter. The square with 12 on blade and 9 on tongue will give the heel and plumb cuts. Another method of finding the length of rafter for the 6 inches is shown in Fig. 16, where the square is shown applied to the rafter Fig. 18. Method of Laying Out Hips and Rafters for Roofs of Various Pitches over Square Corner. THE STEEL SQUARE 13 timber for the plumb cut. Square No. 1 is shown applied with 12 on blade and 9 on tongue for the length of the 13 feet. Square from this cut, measure 6 inches, the additional inches in the run; and to this point move the square, holding it on the side of the rafter timber with 12 on blade and 9 on tongue, as for a full foot run. It will be observed that this method is easily adapted to find any fractional part of a foot in the length of rafters. In the front gable, Fig. 14, the fractional part of a foot is 4 inches to be added to 10 feet of run; therefore, in that case, the line shown measured to 6 inches in Fig. 16 would measure only 4 inches for the front gable. Heel Cut of Common Rafter. In Fig. 16 is also shown a method to lay out the heel cut of a common rafter. The square is shown applied with 12 on blade and 9 on tongue; and from where the 12 on the square intersects the edge of the rafter timber, a line is drawn square to the blade as shown by the dotted line from 12 to a. Then the thickness of the part of the rafter that is to project beyond the plate to hold the cornice, is gauged to intersect the dotted line at a; and from a, the heel cut is drawn v/ith the square having 12 en blade and 9 on tongue, marking along the blade for the cut. The common rafter for the front wing, which is shown to have a run of 10 feet 4 inches, is laid out precisely the same, except that for this rafter the square with 12 on blade and 9 on tongue will have to be stepped along the rafter timber only 10 times for the 10 feet of run; and for the fractional part of a foot (4 inches) which is in the run, either of the two methods already shown for the main rafter may be used. The proportional figures to be used on the square for the 4 inches will be 4 on blade and 2^ on tongue ; and if the second method is used, make the addition to the length of rafter for 10 feet, by drawing a line 4 inches square from the tongue of square No. 1 (see Fig. 16), instead of 6 inches as there shown for the main rafter. Hips. Three of the hips are shown in Fig. 14 to extend from the plate to the ridge-pole; they are marked in the figure as 1, 2, and 3 respectively, and are shown in plan to be diagonals of a square measuring 13 feet 6 inches by 13 feet 6 inches; they make an angle, therefore, of 45 degrees with the plate. 14 THE STEEL SQUARE In Fig. 18 it has been shown that a hip standing at an angle of 45 degrees with the plate will have a run of 17 inches for every foot run of the common rafter. Therefore, to lay out the hips, the figures on the square will be 17 for run and 9 for rise; and by stepping 13 times along the hip rafter timber, the length of hip for 13 feet of run is obtained. The length for the additional 6 inches in the run may be found by squaring a distance of 8 J inches, as shown in Fig. 17, from the tongue of the square, and moving square No; 1 along the edge of the timber, holding the blade on 17 and tongue on 9, and marking the plumb cut where the dotted line is shown. In Fig. 18 is shown how to find the relative run length of a portion of a hip to correspond to that of a frac- tional part of a foot in the length of the common rafter. From 12 inches, measure along the run of the common rafter 6 inches, and drop a line to cut the diagonal line in m. From m to a, along the diagonal line, will be the relative run length of the part of hip to correspond with 6 inches run of the common rafter, and it measures 8J inches. The same results may be obtained by the following method of figuring: As 12 : 17 : : 6 6 19. Diagram Showing Relative Lengths of Run for Hips and Common Rafters in Equal- Pitch Roofs. 12)102 8-6 In Fig. 19 is shown a 12-inch square, the diagonal m being 17 inches. By drawing lines from the base a 6 to cut the diagonal line, the part of the hip to corre- spond to that of the common rafter will be indicated on the line 17. In this figure it is shown that a 6-inch run on ah, which represents the run of a foot of a common rafter, will have a corresponding length of 8i a ^ Fig. 20. Method of Determining Run of Valley for Additional Run in Common Rafter. THE STEEL SQUARE 15 inches run on the hne 17, which represents the plan Hne of the hip or valley in all equal-pitch roofs. In the front gable, Fig. 14, it is shown that the run of the common rafter is 10 feet 4 inches. To find the length of the common rafter, Fig. 21. Corner of Square Building, Show- ing Plan Lines of Plates and Hip. Fig. 23. Corner of Square Building, Show- ing Plan Lines of Plates and Valley. take 12 on blade and 9 on tongue, and step 10 times along the rafter timber; and for the fractional part of a foot (4 inches), proceed as was shown in Fig. 16 for the rafter of the main roof; but in this case measure out square to the tongue of square No. 1, 4 inches instead of 6 inches. The additional length for the fractional 4 inches run can also be found by taking 4 inches on blade and 3 inches on tongue of square, and stepping one time; this, in addition to the length obtained by Heel cut of Valley Fig. 23. Use of Square to Determine Heel Cut of Valley. stepping 10 times along the rafter timber with 12 on blade and 9 on tongue, will give the full length of the rafter for a run of 10 feet 4 inches. In the intersection of this roof with the main roof, there are shown to be two valleys of different lengths. The long one extends from the plate at n (Fig. 14) to the ridge of the main roof at m; it has therefore 16 THE STEEL SQUARE a run of 13 feet 6 inches. For the length, proceed as for the hips, by taking 17 on blade of the square and 9 on tongue, and stepping 13 times for the length of the 13 feet; and for the fractional 6 inches, proceed precisely as shown in Fig. 17 for the hip, by squaring out from the tongue of square No. 1, 8 J inches; this, in addition to the length obtained for the 13 feet, will give the full length of the long valley n m. The length of the short valley a c, as shown, extends over the run of 10 feet 4 inches, and butts against the side of the long valley at e. By taking 17 on blade and 9 on tongue, and stepping along the rafter timber 10 times, the length for the 10 feet is found; and for the 4 inches, measure 5f inches square from the tongue of square No. 1, in the manner shown -ID 1 * V* c.- in Fier. 17, where - z' Bevel to fit hips . Z^ against a deep the 8 J inches is ^ roof or Tid^eboard shown added for the 6 inches addi- tional run of the main roof for the hips. The length 5f is found as shown in Fig. 20, by meas- uring 4 inches from a to m along the run of common rafter for one foot. Upon m erect a line to cut the seat of the valley at c; from c to a will be the run of the valley to correspond with 4 inches run of the common rafter, and it will measure 5f inches. How to Treat the Heel Cut of Hips and Valleys. Having found the lengths of the hips and valleys to correspond to the common rafters, it will be necessary to find also the thickness of each above the plate to correspond to the thickness the common rafter will be above the plate. In Fig. 21 is shown a corner of a square building, showing the plates and the plan lines of a hip. The length of the hip, as already found, will cover the span from the ridge to the corner 2; but the sides Fig. 24. Steel Square Applied to Finding Bevel for Fitting Top of mp or Valley to Ridge. THE STEEL SQUARE 17 of the hip intersect the plates at 3 and 3 respectively; therefore the distance from 2 to 1 , as shown in this diagram, is measured backwards from a to 1 in the manner shown in Fig. 17; then a plumb line is drawn through 1 to m, parallel to the plumb cut a-17. From m to o on this line, measure the same thickness as that of the common rafter; and through draw the heel cut to a as shown. In like manner the thickness of the valley above the plate is found ; but as the valley as shown in the plan figure. Fig. 22, projects beyond point 2 before it intersects the outside of the plates, the distance from 2 to 1 in the case of the valley will have to be measured outwards from 2, as shown from 2tol in Fig. 23; and at the point thus found the thickness of the valley is to be measured to cor- respond with that of the com- mon rafter as shown at m n. In Fig. 24 is shown the steel square applied to a hip or valley timber to cut the bevel that will fit the top end against the ridge. The figures on the square are 17 and 19 J. The 17 represents the length of the plan line of the hip or valley for a foot of run, which, as was shown in previous figures,, will always be 17 inches in roofs of equal pitch, where the plan lines stand at 45 degrees to the plates and square to each other. The 19i taken on the blade represents the actual length of a hip o-r valley that will span over a run of 17 inches. The bevel is marked along the blade. The cut across the back of the short valley to fit it against the side of the long valley, will be a square cut owing to the two plan lines being at right angles to each other. ^jj /"Bevel tofitbacK ^ -1/ of jacks against hip or valley Fig. 25. Steel Square Applied to Jack Rafter to Find Bevel for Fitting against Side of Hip or Valley. 18 THE STEEL SQUARE In Fig. 25 is shown the steel square applied to a jack rafter to cut the back bevel, to fit it against the side of a hip or valley. The figures on the square are 12 on tongue and 15 on blade, the 12 repre- senting a foot run of a common rafter, and the 15 the length of a rafter that will span over a foot run; marking along the blade will give the bevel. The rule in every case to find the back bevel for jacks in roofs of equal pitch, is to take 12 on the tongue to represent the foot run^ and the length of the rafter for a foot of run on the blade, marking along the blade in each case for the bevel. In a J-pitch roof, which is the most common in ah parts of the Run of Rafter Fig. 26. Finding Length to Shorten Rafters for Jacks per Foot of Run. country, the length of rafter for a \ foot of run will be 1 7 inches ; hence it will be well to remember that 12 on tongue and 17 on blade, marking along the blade, will give the bevel to fit a jack against a hip or a valley in a J-pitch roof. In a roof having a rise of 9 inches to the foot of run, such as the one under consideration, the length of rafter for one foot of run will be 15 inches. The square as shown in Fig. 25, with 12 on tongue and 15 on blade, will give the bevel by marking along the blade. To find the length of a rafter for a foot of run for any other pitch, place the two-foot rule diagonally from 12 on the blade of the square to the figure on tongue representing the rise of the roof to the foot of run; the rule will give the length of the rafter that will span over one foot of run. The length of rafter for a foot of run will also determine the difference in lengths of jacks. For example, if a roof rises 12 inches to one foot of run, the rafter over this span has been found to be 17 inches; this, therefore, is the number of inches each jack is shortened in one foot of run. If the rise of the roof is 8 inches to the foot of run, the length of the rafter is found for one foot of run, by placing the rule diagonally from 12 on Fig. 27. Finding Length of Jack Rafter in >^-Pitch Roof. THE STEEL SQUARE 19 tongue to 8 on blade, which gives 14J inches, as shown in Fig. 26. Tliis, therefore, will be the number of inches the jacks are to be shortened in a roof rising 8 inches to the foot of run. If the jacks are placed 24 inches from center to center, then multiply 14^ by 2 = 29 inches. In Fig. 27 is shown how to find ^Q ^ the length with the steel square. The square is placed on the jack timber rafter with the figures that have been ^ used to cut the common rafter. In Fig. 27, 12 on blade and 12 on tongue were the figures used to cut the com- mon rafter, the roof being ^ pitch, rising 12 inches to the foot of run. In the diagram it is shown how to find the length of a jack rafter if placed 16 inches from center to center. The method is to move the square as shown along the line of the blade until the blade measures 16 inches; the tongue then would be as shown from w to m, and the length of the jack would be from 12 on blade to m on tongue, on the edge of the jack rafter timber as shown. This latter method becomes convenient w^hen the space between jacks is less than 18 inches; but if used when the space is more than Fig. 28. Finding Length of Jack Rafter in %-Pitch Roof. Ridq /Valley V k Plate' Fig= 29. Method of Determining Length of Jacks Between Hips and Valleys; also Bevels for Jacks, Hips, and Valleys. 18 inches it will become necessary to use two squares; otherwise the tongue as shown at m would not reach the edge of the timber. In Fig. 28 the same method is shown for finding the length of a jack rafter for a roof rising 9 inches to the foot of run, with the jacks placed 18 inches center to center. The square in this diagram is shown placed on the jack rafter timber with 12 on blade and 9 on 20 THE STEEL SQUARE tongue; then it is moved forward along the Hne of the blade to w. The blade, when in this latter position, will measure 18 inches. The tongue will meet the edge of the timber at m, and the distance from m on tongue to 12 on blade will indicate the length of a jack, or, in other words, will show the length each jack is shortened when placed Miter Bevel for Boards Bevel to cut the Rn^rH Back Bdvel for Jacks *, Fig. 30. Method of Finding Bevels for All Timbers in Roofs of Equal Pitch. 18 inches between centers in a roof having a pitch of 9 inches to the foot of run. When jacks are placed between hips and valleys as shown at 1, 2, 3, 4, etc., in Fig. 14, a better method of treatment is shown in Fig. 29, where the slope of the roof is projected into the horizontal plane. The distance from the plate in this figure to the ridge m, equals the length of the common rafter for the main roof. On the plate ann is made equal to a ti n in Fig. 14. By drawing a figure like this to a scale of one inch to one foot, the length of all the jacks can be measured THE STEEL SQUARE 21 Side cut of hip aqainst t'he "*" ridqe board and also the lengths of the hip and the two valleys. It also gives the bevels for the jacks, as well as the bevel to fit the hip and valley against the ridge; but this last bevel must be applied to the hip and valley when backed. It has been shown before, thiit the figures to be used on the square for this bevel when the timber is left square on back as is the custom in construction, are the length of a foot run of a hip or val- ley, which is 17, on tongue, and the length of a hip or valley that will j span over 17 inches run, on blade — the blade giving the bevel. Fig. 30 contains all the bevels or cuts that have been treated upon so far, and, if correctly understood, will enable any one to frame any roof of equal pitch. In this figure it is shown that 12 inches run and 9 inches rise will give bevels 1 and 2, which are the plumb and heel cuts of rafters of a roof rising 9 inches to the foot of run. By taking these figures, therefore, on the square, 9 inches on the tongue and 12 inches on the blade, marking along the tongue will give the plumb cut, and marking along the blade will give the heel cut. Bevels 3 and 4 are the plumb and heel cuts for the hip, and are shown to have the length of the seat of hip for one foot run, which is 17 inches. By taking 17 inches, therefore, on the blade, and 9 inches on the tongue, marking along the tongue for the plumb cut, and along Miter cut for roo< board Fig. 31, Method of Finding Bevel 5, Fig. 30, for Fitting Hip or Valley Against Ridge when not Backed. Fig. 33. Method of Finding Baclc Bevel 6, Fig. 30, for Jack Rafters, and Bevel 7, for Roof-Board. Fig. 33. Determining Miter Cut for Roof- Board. the blade for the heel cut, the plumb and heel cuts are found. Bevel 5, which is to fit the hip or valley against the ridge when not backed, is shown from o w, the length of the hip for one foot of run, which is 19i inches, and from o s, which always in roofs of equal pitch will be 17 inches and equal in length to the seat of a hip or valley for one foot of run. 22 THE STEEL SQUARE These figures, therefore, takei the 19^ the blade, Laying Out. Timbers of One-half Gable of %-Pitch Roof. square, and 17 on the tongue, will give the bevel by marking along the blade as shown in Fig. 31, where the square is shown applied to the hip timber with 19 J on blade and 17 on tongue, the blade showing the cut. Bevels 6 and 7 in Fig. 30 are shown formed of the length of the rafter for one foot of run, which is 15 inches, and the run of the rafter, which is 12 inches. These figures are applied on the square, as shown in Fig. 32, to a jack rafter tim- ber; taking 15 on the blade and 12 on the tongue, marking along the blade will give the back bevel for the jack rafters, and marking along the tongue will give the face cut of roof -boards to fit along the hip or valley. It is shown in Fig. 30, also, that by taking the length of rafter 15 inches on blade, and rise of roof 9 inches on tongue, bevel 8 will give the miter cut for the roof-boards. In Fig. 33 the square is shown applied to a roof-board with 15 on blade, which is the length of the rafter to one foot of run, and with 9 on tongue, which is the rise of the roof to the foot run; marking along the tongue will give the miter for the boards. Other uses may be made of these figures, as shown in Fig. 34, which is one-half of a gable of a roof ris- ing 9 inches to the foot run. The squares at the bottom and the top will give the plumb and heel cuts of the common rafter. The same figures on the square applied to the studding, marking along the tongue for the cut, will give the bevel to fit the studding against the rafter; and by marking along the blade we obtain the cut for the boards that run across the gable. By taking 19 J on blade, which is Fig. 35. Finding Backing of Hip in Gable Roof. THE STEEL SQUARE 23 the lengith of the hip for one foot of run, and taking on the tongue the rise of tlio roof to the foot of run, which is 9 inches, and applying these as shown in Fig. 35, we obtain the backing of the hip by marking along the tongue of the two squares, as shown. It will be observed from what has been said, that in roofs of equal pitch the figure 12 on the blade, and whatever number of inches the roof rises to the foot run on the t')ngue, will give the plumb and heel cuts for the common rafter; and that by taking ;.7 on the blade instead of 12, and taking on the tongue the figure representing the rise of the roof to the foot run, the plumb and heel cuts are found for the hips and valleys. By taking the length of the common rafter for one foot of run on blade, and the run 12 on tongue, marking along the blade will give 6 e Fig. 36. Laying Out Timbers of Roof with Two Unequal Pitches. the back bevel for the jack to fit the hip or valley, and marking along the tongue will give the bevel to cut the roof-boards to fit the line of hip or valley upon the roof. With this knowledge of what figures to use, and why they are used, it w^ill be an easy matter for anyone to lay out all rafters for equal-pitch roofs. In Fig. 36 is shown a plan of a roof with two unequal pitches. The main roof is shown to have a rise of 12 inches to the foot run. The front wing is shown to have a run of 6 feet and to rise 12 feet; it has thus a pitch of 24 inches to the foot run. Therefore 12 on blade of the square and 12 on tongue will give the plumb and heel cuts for the main roof, and by stepping 12 times along the rafter timber the length of the rafter is found. The figures on the square to find the heel and 24 THE STEEL SQUARE plumb cuts for the rafter in the front wing, will be 12 run and 24 rise, and by stepping 6 times (the number of feet in the run of the rafter), the length will be found over the run of 6 feet, and it will measure 13 feet 6 inches. If, in place of stepping along the timber, the diagonal of 12 and 24 is multiplied by 6, the number of feet in the run, the length may be found even to a greater exactitude. Many carpenters use this method of framing; and to those who have confidence in their ability to figure correctly, it is a saving of time, and, as before said, will result in a more accurate measurement; but the better and more scientific method of framing is to work to a scale of one inch, as has already been explained. According to that method, the diagonal of a foot of run, and the number of inches to the foot run the roof is rising, measured to a scale, will give the exact length. For example, the main roof in Fig. 36 is rising 12 inches to a foot of run. The diagonal of 12 and 12 is 17 i I I I I I I Fig. 37. Finding Length of Rafter for Front Wing in Roof Shown in Fig. 36. inches, which, considered as a scale of one inch to a foot, will give Fig. 38. Laying Out Timbers of Roof Shown in Fig. 36, by Projecting Slope of Roof into Horizontal Plane. 17 feet, and this will be the exact length of the rafter for a roof rising 12 inches to the foot run and having a run of 12 feet. The length of the rafter for the front wing, which has a run of 6 feet and a rise of 12 feet, may be obtained by placing the rule as shown THE STEEL SQUARE 25 Elevation in Fig. 37, from 6 on blade to 12 on tongue, which will give a length of 13i inches. If the scale be considered as one inch to a foot, this will equal 13 feet 6 inches, which will be the exact length of a common rafter rising 24 inches to the foot run and having a run of 6 feet. It will be observed that the plan lines of the valleys in this figure in respect to one another deviate from forming a right angle. In equal-pitch roofs the plan lines are always at right angles to each other, and therefore the diagonal of 12 and 12, which is 17 inches, will be the relative foot run of valleys and hips in equal-pitch roofs. In Fig. 36 is shown how to find the figures to use on the square for valleys and hips when deviating from the right angle. A line is drawn at a distance of 12 inches from the plate and parallel to it, cutting the valley in m as shown. The part of the valley from m to the plate will measure 13J inches, which is the figure that is to be used on the square to obtain the length and cuts of the valleys. It will be observed that this equals the length of the common rafter as found by the square and rule in Fig. 37. In that figure is shown 12 on tongue and 6 on blade. The 12 here represents the rise, and the 6 the run of the front roof. If the 12 be taken to represent the run of the main roof , and the 6 to represent the run of the front roof, then, the diagonal 13 J will indi- cate the length of the seat of the valley for 12 feet of run, and there- fore for one foot it will be 13 J inches. Now, by taking 13^ on the blade for run, and 12 inches on the tongue for rise, and stepping along the valley rafter timber 12 times, the length of the valley will be found. The blade will give the heel cut, and the tongue the plumb cut. In Fig. 38 is shov/n the slope of the roof projected into the hori- zontal plane. By drawing a figure based on a scale of one inch to one Fig. 39. Method of Finding Length and Cuts of Octagon Hips Intersect- ing a Roof. 26 THE STEEL SQUARE foot, all the timbers on the slope of the roof can be measured. Bevel 2, shown in this figure, is to fit the valleys against the ridge. By drawing a line from w square to the seat of the valley to m, making ^ Ridge in vSecon d POvSition r~^^^ c Cornice Fig. 40, Showing How Cornice Aflects Valleys and Plates in Roof with Unequal Pitches. 10 2 equal in length to the length of the valley, as shown, and by con- necting 2 and m, the bevel at 2 is found, which will fit the valleys against the ridge, as shown at 3 and 3 in Fig. 36. In Fig. 39, is shown how to find the length and cuts of octagon hips intersecting a roof. In Fig. 36, half the plan of the octagon is shown to be inside of the plate, and the hips o, 2, o intersect the slope of the roof. In Fig. 39, the lines below x y are the plan lines; and those above, the elevation. From 2, o. o, in the plan, draw lines to x y, as shown from o to m and from z to m; from m and m, draw the ele- vation lines to the apex o", inter- secting the line of the roof in d" and c''. From c^'' and c", draw the lines d" v" and c" a" parallel io X y\ from c", drop a line to in- tersect the plan line ao in c. Make a w equal in length to a" o" of the elevation, and connect \o c; Fig. 41. Showing Relative Position of i p n i • i Plates in Roof with Two un- measure irom w to 71 the lull neignt equal Pitches. " of the octagon as shown from xy to the apex o"; and connect c n. The length from lo to c is that of THE STEEL SQUARE 27 the two hips shown at o o in Fig. 36, both being equal hips intersect- ing the roof at an equal distance from the plate. The bevel at'w;is the top bevel, and the bevel at c will fit the roof. Again, drop a line from d'^ to intersect the plan line azind. Make a 2 equal to v'^ o" in the elevation, and connect 2 d. Measure from 2 to 6 the full height of the tower as shown from xyio the apex o" in the elevation, and connect d b. Seat ofVa-lley Fig. 43. The length 2 d represents the length of the hip z shown in Fig. 36; the bevel at 2 is that of the top ; and the bevel at d, the one that will fit the foot of the hip to the intersecting roof. When a cornice of any con- siderable width runs around a roof of this kind, it affects the plates and the angle of the val- leys as shown in Fig. 40. In this figure are shown the same valleys as in Fig. 36 ; but, owing to the width of the cornice, the foot of each has been moved the distance a b along the plate of the main roof. Why this is done is shown in the drawing to be caused by the necessity for the valleys to intersect the corners c c of the cornice. The plates are also affected as shown in Fig. 41, where the plate of the narrow roof is shown to be much higher than the plate of the main roof. ' The bevels shown at 3, Fig. 40, are to fit the valleys against the ridge. In Fig. 42 is shown a very simple method of finding the bevels for purlins in equal-pitch roofs. Draw the plan of the corner as shown, and a line from m to o; measure from o the length x y, representing the common rafter, to w; from w draw a line to m; the bevel shown at 2 will fit the top face of the purlin. Again, from o, describe an arc to cut the seat of the valley, and continue same around to S; con- nect S m; the bevel at 3 will be the side bevel. Method of Finding Bevels for Pur- lins in Equal-Pitch Roofs. EXAMINATION PAPER THE STEEL SQUARE Read Carefully: Place your name aud full address at the head of the paper. Anj^ cheap, light paper like the sample previously seutyou may be used. Do uot crowd your work, but arrange it neatly and legibly. Do not copy the ansivers from the Instruction Paper; use your oivn words, so that we may be sure that you understand the subject. 1. On what part of the square will you find the octagon scalef Describe its use. 2. On what part of the square will you find the brace rule? Describe its use. 3. On what part of the square would you look for the hoard measure? Describe its use. 4. What is meant by the pitch of a roof? 5. What is meant by a bevel in roof framing? 6. Draw a diagram of a roof, indicating thereon the ridge, common rafters, jack rafters, hips, valleys, plate. 7. How would you lay out a pentagon by means of the square? A hexagon? Illustrate with diagrams. 8. How, with a square, would you find the miter of an equi- lateral triangle? Of a hexagon? Illustrate with diagrams. 9. What are meant by plumb cut and heel cut? Draw a diagram to illustrate. 10. Show how to lay out the heel cut of a common rafter. 11. Draw diagrams illustrating use of the square in finding the relative length of run for rafters and hips. Explain. 12. Show how to apply the square to a hip or valley timber to cut the bevel that will fit the top end against the ridge. 13. Describe the application of the square in finding the relative height of a hip or valley per foot of run, to that of the common rafter. Draw a diagram. 14. Describe a method of finding the bevels for purlins in equal-pitch roofs. 15. Describe, with diagram, the use of the square in cutting the back bevel to fit a jack rafter against the side of a hip or valley. THE STEEL SQUARE 16. How would you use the square to find the length to cut jack rafters in roofs of J-pitch? |-pitch? 17. Show how to find the length and cuts of octagon hips intersecting a roof. After completing the work, add and sign the following statement : I hereby certify that the above work is entirely my own. (Signed) JUN 13 1908 ^/ LIBRARY OF CONGRESS 028 145 854 1